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Find m∠MON
I have a hard time with theses

Find m∠MON I have a hard time with theses-example-1

1 Answer

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Answer:

m∠MON = 15°

Explanation:

The given parameters are;

m∠LON = 77°

m∠LOM = 9·x + 44°

m∠MON = 6·x + 3°

By angle addition postulate, we have;

m∠LON = m∠LOM + m∠MON

Therefore, by substituting the known values, we have;

∴ 77° = 9·x + 44° + 6·x + 3°

77° = 9·x + 44° + 6·x + 3° = 15·x + 47°

77° = 15·x + 47°

77° - 47° = 15·x

15·x = 77° - 47° = 30°

15·x = 30°

x = 30°/15 = 2°

x = 2°

Given that m∠MON = 6·x + 3° and x = 2°, we have;

m∠MON = 6 × 2° + 3° = 12° + 3° = 15°

m∠MON = 15°.

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