Question

The head of a 245 g golf club traveling at 62 m/s just before it strikes a 48 g golf ball at rest on a tee. After the collision, the club travels in the same direction at 43 m/s. Use the law of conservation of momentum find the speed of the golf ball just after impact.

Answer 1

The speed of the golf ball just after impact is 96.98 m/s

Step-by-step explanation:

Given;

mass of the club, m₁ = 245 g = 0.245 kg

initial velocity of the club, u₁ = 62 m/s

mass of the golf ball, m₂ = 48 g = 0.048 kg

initial velocity of the golf ball, u₂ = 0

final velocity of the club, v₁ = 43 m/s

let the final velocity of the golf ball

Apply the law of conservation of momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.245(62) + (0.048 x 0) = 0.245(43) + 0.048v₂

15.19 = 10.535 + 48v₂

15.19 - 10.535 = 48v₂

4.655 = 48v₂

v₂ = 4.655 / 0.048

v₂ = 96.98 m/s

Therefore, the speed of the golf ball just after impact is 96.98 m/s