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Hi. I need help with these questions.
See age for question.
Answer 11,12

Hi. I need help with these questions. See age for question. Answer 11,12-example-1

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Answer:

  • 11) k = -1
  • 12) (i) 4, (ii) 6.5

Explanation:

11. ......................................................

Given equation

  • x² + (k - 1)x - k = 0
  • The roots are equal

To find

  • The value of k

Solution

When the roots are equal, the discriminant equals zero

  • D = 0
  • b² - 4ac = 0

Substituting the values and solving for k:

  • (k - 1)² - 4*1*(-k) = 0
  • k² - 2k + 1 - 4k = 0
  • k² + 2k + 1 = 0
  • (k + 1)² = 0
  • k + 1 = 0
  • k = -1

12. ......................................................

Given equation

  • 2x² - 6x + 1 = 0
  • The roots are α and β

To find

The values of

  • (i) 2αβ² + 2α²β + 2αβ
  • (ii) α² - 3αβ + β²

Solution

The sum and the product of the roots is:

  • α + β = - b/a = - ( - 6)/2 = 3
  • αβ = c/a = 1/2

(i)

  • 2αβ² + 2α²β + 2αβ =
  • 2αβ ( α + β + 1) =
  • 2(1/2)(3 + 1) =
  • 1(4) =
  • 4

(ii)

  • α² - 3αβ + β² =
  • (α + β)² - 5αβ =
  • 3² - 5(1/2) =
  • 9 - 5/2 =
  • 6.5
User Umair Abid
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