Question

F(x)=x^2+12x+35, solve f(x)>0

Answer 1

Explanation:

• Solve the eq f(x) =0

x^2+5x+7x+35=0

x*x+5x+7x+5*7=0

x(x+5)+7(x+5)=0

(x+7)*(x+5)=0

x=-7 or x=-5

• Now solve f(x) >0

So the function is positive (>0) when

x<-7 and when x>-5