Answer:
![t=(9\pm 3)/(6)](https://img.qammunity.org/2021/formulas/mathematics/college/8smmaoduw20gkjrd2xrq2m5zwfwtnsbq3p.png)
![1\ \text{hour}](https://img.qammunity.org/2021/formulas/mathematics/college/5f6ejdb78sf6b7ykvaekdupkpemitqcdvt.png)
![2\ \text{hour}](https://img.qammunity.org/2021/formulas/mathematics/college/qphhq4p7je1kgv7wtehyqgudi04prv6dhq.png)
Explanation:
s = Speed of Emile = 6 miles/hour
d = Distance traveled by Emile =
![(9\pm 3)\ \text{miles}](https://img.qammunity.org/2021/formulas/mathematics/college/wura8q45bs89q2u5498jpjuzy8x7dknvnl.png)
Time taken to find the minimum and maximum time Emile ran for is
![t=(d)/(s)\\\Rightarrow t=(9\pm 3)/(6)](https://img.qammunity.org/2021/formulas/mathematics/college/ym2vvqrq1l4v67vraw3lvyhoesrf6k9cug.png)
The required equation is
![t=(9\pm 3)/(6)](https://img.qammunity.org/2021/formulas/mathematics/college/8smmaoduw20gkjrd2xrq2m5zwfwtnsbq3p.png)
The time taken is
![t=(9-3)/(6)\\\Rightarrow t=(6)/(6)\\\Rightarrow t=1\ \text{hour}](https://img.qammunity.org/2021/formulas/mathematics/college/gcszyzlclln4sf97w2l2ltxsnfwu4vni5h.png)
The minimum number of hours Emile runs is 1 hour.
![t=(9+3)/(6)\\\Rightarrow t=(12)/(6)\\\Rightarrow t=2\ \text{hour}](https://img.qammunity.org/2021/formulas/mathematics/college/tdalap5lsgq380k5tqzd8gbmre2zbxrsxo.png)
The maximum number of hours Emile runs is
.