Question

The is factoring quadratics with a leading coefficient: 5x to the 2 power - 14x + 8

Answer 1

The factorization of
`5x^2-14x+8` is (5x-4)(x-2)

Explanation:

Given quadratic polynomial is:

`5x^2-14x+8`

To factor a quadratic polynomial with leading co-efficient has to be factorized, the leading co-efficient and the constant are multiplied and pairs(a,b) of the product are made so that their sum or subtraction is equal to the co-efficient of x

We get 40 by multiplying 8 and 5

And the pair we get are: 10 and 4

`=5x^2-10x-4x+8\\=5x(x-2)-4(x-2)\\=(5x-4)(x-2)`

Hence,

The factorization of
`5x^2-14x+8` is (5x-4)(x-2)