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Means and SDs. For each part, compare distributions (1) and (2) based on their means and standard deviations. You do not need to calculate these statistics; simply state how the means and the standard deviations compare.

A)


1) 3, 5, 5, 5, 8, 11, 11, 11, 132) 3, 5, 5, 5, 8, 11, 11, 11, 20B)1) -20, 0, 0,0,15, 25, 30, 302) -40, 0,0, 0,15, 25, 30,30


C)


1) 0,2,4,6,8,10


2) 20, 22, 24, 26, 28, 30


D)


1) 100, 200, 300, 400, 500


2) 0, 50, 300, 550, 600

User Neen
by
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1 Answer

4 votes

Answer:

hfiwadhcase9iskoalsuhc;AJDSLASHDOIAWNHEOJOSED

Explanation:

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User Frank Kotler
by
5.2k points