Answer:
The number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
Step-by-step explanation:
Given;
intensity of the sunlight, I = 2.00 kJ·s−1·m^−2
area of incident, A = 5.2 cm² = 5.2 x 10⁻⁴ m²
Energy of incident photons per second on the given area;
E = IA
E = (2000)( 5.2 x 10⁻⁴)
E = 1.04 J/s
Energy of a photon is given is by;

The number of photons per second that strike the given area is;

Therefore, the number of photons per second that strike the given area is 2.668 x 10⁸ photons/second