Answer:
A) 0.889
B) 0.895
Explanation:
Mean of 53.8 inches, and Standard deviation of 7.5 inches.
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
A) What is the probability that a randomly chosen child has a height of less than 62.95 inches?
For x < 62.95
z = 62.95 - 53.8/7.5
z = 1.22
Probabilityvalue from Z-Table:
P(x<62.95) = 0.88877
Approximately = 0.889
B) What is the probability that a randomly chosen child has a height of more than 44.4 inches?
For x > 44.4 inches
z = 44.4 - 53.8/7.5
z = -1.25333
Probability value from Z-Table:
P(x<44.4) = 0.10504
P(x>44.4) = 1 - P(x<44.4) = 0.89496
Approximately = 0.895