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In wet mill ethanol plants, a total energy of 74,488 Btu (British thermal units, a common energy unit) is used to produce 1 gallon of ethanol. If ethanol can provide 76,330 Btu per gallon, what is the net energy yield for one gallon of ethanol?

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Answer:

The energy yield for one gallon of ethanol is 2.473 %.

Step-by-step explanation:

The net energy yield (
\% e), expressed in percentage for one gallon of ethanol is the percentage of the ratio of the difference of the provided energy (
E_(g)), measured in Btu, and the energy needed to produce the ethanol (
E_(p)), measured in Btu, divided by the energy needed to produce the ethanol. That is:


\% e =(E_(g)-E_(p))/(E_(p)) * 100\,\% (1)

If we know that
E_(g) = 76330\,Btu and
E_(p) = 74488\,Btu, then the net energy yield of 1 gallon of ethanol:


\%e = (76330\,Btu-74488\,Btu)/(74488\,Btu)* 100\,\%


\%e = 2.473\,\%

The energy yield for one gallon of ethanol is 2.473 %.

User Nicolas Hauzaree
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