Question

What is the enrgy change when the temperature of 14.4 grams of solid alumnum is decreased from 39.5°C to 23.0°C?

Answer 1

`Q=-213.84J`

Step-by-step explanation:

Hello!

In this case, since energy involved when a substance undergoes a temperature change due to heat addition or removal is computed as shown below:

`Q=mC\Delta T`

As the aluminum has a specific heat of 0.900 J/g°C and 14.4 g underwent such temperature decrease, the energy change is:

`Q=14.4g*0.900(J)/(g\°C)(23.0\°C-39.5\°C)\\\\Q=-213.84J`

Which is an outlet energy flow.

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