Can u explain how to solve this?

Question

asked Dec 4, 2021 159k views

1 Answer

Robert Wagner · Answer 1 · 2021-12-08T17:06:52+0000

Answer: B.pi/2

ABCD is a square

=> Δ ABD is a isosceles right triangle at A

using pythago theorem, we have:

AB² + AD² = BD²

=> 2AD² = 4

⇔ AD² = 2

⇒ AD = √2

through O, draw EF parallel to AD and BC

=> EF is diameter

because EF//AD => EF = AD = √2 (because circle O is inscribed the square ABCD)

=> the area of the circle is
$S=((√(2))^(2) )/(4).\pi =(\pi )/(2)$

Explanation: