Question

An animal cell placed in a hypertonic solution will shrink in a process called crenation. An animal cell placed in a hypotonic solution will swell and potentially burst in a process called hemolysis. To prevent crenation or hemolysis, an animal cell must be placed in an isotonic solution such as 0.9% (m/v) NaCl or 5.0% (m/v) glucose. This does not mean that a cell has a 5.0% (m/v) glucose concentration; it just means that 5.0% (m/v) glucose will exert the same osmotic pressure as the solution inside the cell, which contains several different solutes. A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur.

Solution A: 3.21% (m/v) NaCl
Solution B: 1.65% (m/v) glucose
Solution C: distilled H2O
Solution D: 6.97% (m/v) glucose
Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl
Drag each solution to the appropriate bin.

Answer 1

Solution A: 3.21% (m/v) NaCl ⇒ CRENATION

Solution B: 1.65% (m/v) glucose ⇒ HEMOLYSIS

Solution C: distilled H₂O ⇒ HEMOLYSIS

Solution D: 6.97% (m/v) glucose ⇒ CRENATION

Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl ⇒ CRENATION

Step-by-step explanation:

Isotonic solution = 0.9% (m/v) NaCl or 5.0% (m/v) glucose

Crenation will occur if the solution has a concentration higher than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypertonic solution). This will occur in the following solutions:

Solution A: 3.21% (m/v) NaCl > 0.9% (m/v) NaCl

Solution D: 6.97% (m/v) glucose > 5.0% (m/v) glucose

Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl (the addition of the 2 components exceeds the osmotic pressure permitted).

Hemolysis will occur if the solution has a concentration lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypotonic solution). This is the case of:

Solution B: 1.65% (m/v) glucose < 5.0% (m/v) glucose

Solution C: distilled H₂O = 0% glucose/0% NaCl < 0.9% (m/v) NaCl or 5.0% (m/v) glucose