Question

Help please!!! ON THISSS (i will report you if not answered seriously) :))

Answer 1

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`XCV \: \: angle = (XWV \: \: arc)/(2) \\`

Multiply sides by 2

`2 \: XCV \: \: angle = XWV \: \: arc`

`XWV \: \: arc = 2 × XCV \: \: angle \\`

`XWV \: \: arc = 156°`

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`XWV \: \: arc + VCX \: \: arc = 360° \\`

`156° + VCX \: \: arc = 360°`

Subtract sides 156°

`-156° + 156° + VCX \: \: arc = -156° + 360° \\`

`VCX \: \: arc = 204°`

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`XWV \: \: angle = (XCV \: \: arc)/(2) \\`

`17x = (204)/(2) \\`

`17x = 102`

Divide sides by 17

`(17x)/(17) = (102)/(17) \\`

`x = 6`

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Sum of the interior angles of XWVC equal 360° .

Thus in XWVC :

`X + W + V + C = 360°`

`(9y) + (17x) + (6y) + (78°) = 360° \\`

`15y + 17x + 78° = 360°`

`15y + 17(6) + 78° = 360°`

`15y + 102° + 78° = 360°`

`15y + 180° = 360°`

Subtract sides 180°

`15y + 180° - 180° = 360° - 180° \\`

`15y = 180°`

Divide sides by 15

`(15y)/(15) = (180)/(15) \\`

`y = 12`

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`X = 9y`

`X = 9(12)`

`X = 108°`

`V = 6y`

`V = 6(12)`

`V = 72°`

`W = 17x`

`W = 17(6)`

`W = 102°`

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