Question

(45x-7)4x=57 solve this and ill make out with you

Answer 1

After solving
`(45x-7)4x=57` we get
`\mathbf{x=0.645 \ or \ x = -0.490}`

Explanation:

We need to solve the equation:
`(45x-7)4x=57`

Solving:

`(45x-7)4x=57`

Multiply 4x with terms inside the bracket

`180x^2-28x=57`

`180x^2-28x-57=0`

We need to solve above equation to find value of x

Using quadratic formula for finding value of x:
`x=(-b\pm√(b^2-4ac))/(2a)`

We have a=180, b=-28 and c=-57

`x=(-b\pm√(b^2-4ac))/(2a)\\x=(-(-28)\pm√((-28)^2-4(180)(-57)))/(2(180))\\x=(28\pm√(784+41040))/(360)\\x=(28\pm√(41824))/(360)\\x=(28\pm204.51)/(360)\\x=(28+204.51)/(360) \ or \ x=(28-204.51)/(360)\\x=0.645 \ or \ x = -0.490`

Values of x are
`\mathbf{x=0.645 \ or \ x = -0.490}`

So, After solving
`(45x-7)4x=57` we get
`\mathbf{x=0.645 \ or \ x = -0.490}`