Answer:
The answers are:
![a) (1001111)_2 = (79 )_(10)\\b) (11000001)_2 = (C1 )_(16)\\c) (E16)_(16) = ( 3606)_(10)\\d) (56)_(10) = (38 )_(16)\\e) (63)_(10)= (111111 )_2](https://img.qammunity.org/2021/formulas/computers-and-technology/college/w2h2g23itve1v1k3gpfgelddt9wkohnjl1.png)
Step-by-step explanation:
a. (1001111) 2 = ( ) 10
In order to convert a base 2 number to base 10 number system the place values are used.
the procedure is as follows:
![(1001111)_2\\=(1*2^6)+(0*2^5)+(0*2^4)+(1*2^3)+(1*2^2)+(1*2^1)+(1*2^0)\\=(1*64)+(0*32)+(0*16)+(1*8)+(1*4)+(1*2)+(1*1)\\=64+0+0+8+4+2+1\\=79](https://img.qammunity.org/2021/formulas/computers-and-technology/college/cfcfwqb0joszad0dy5yvwnmew5fc6ar22s.png)
b) (11000001) 2 = ( ) 16
In order to convert a base 2 number into base 16, group of 4-bits are made starting from right to left
The groups from the given number are:
1100 0001
Then the groups are changed in to decimal/hexa
So,
![(1100)_2 = (1*2^3)+(1*2^2)+(0*2^1)+(0*2^0)\\=(1*8)+(1*4)+(0*2)+(0*1)\\=8+4+0+0=12=C\\\\0001=1](https://img.qammunity.org/2021/formulas/computers-and-technology/college/496nbssvkw95oovtuqdu8xq7t13wt8h5ay.png)
Writing in the same order in which groups were:
![(C1)_(16)](https://img.qammunity.org/2021/formulas/computers-and-technology/college/nbd90sb1d59db7lqv1zxj7qmcw2hk9wn78.png)
c) (E16) 16 = ( ) 10
![(E16)_(16)\\=(E*16^2)+(1*16^1)+(6*16^0)\\=(E*256)+(1*16)+(6*1)\\=3584+16+6\\=3606](https://img.qammunity.org/2021/formulas/computers-and-technology/college/cmmq6s66c3mi9ybkpy3v2cbtblghhz0bbd.png)
d) (56) 10 = ( ) 16
Dividing by 16 and noting remainders
16 56
3 - 8
So,
The number in base 16 is 38
e) (63) 10 = ( ) 2
Dividing by 2
2 63
2 31 - 1
2 15 - 1
2 7 - 1
2 3 - 1
1 - 1
So the number after converting in base 2 is:
111111
Hence,
The answers are:
![a) (1001111)_2 = (79 )_(10)\\b) (11000001)_2 = (C1 )_(16)\\c) (E16)_(16) = ( 3606)_(10)\\d) (56)_(10) = (38 )_(16)\\e) (63)_(10)= (111111 )_2](https://img.qammunity.org/2021/formulas/computers-and-technology/college/w2h2g23itve1v1k3gpfgelddt9wkohnjl1.png)