158k views
0 votes
The population of a country in 2009 was 642000 and it was increased by 5 % in 2010.

i-Find increase in population.



ii-How much was the population in 2010.


iii-Find percentage of increase over the population of 2009



User Schummar
by
8.1k points

1 Answer

7 votes

Answer:

i) 32100 people

ii) 674100

iii) 5%

Explanation:

The population in 2009 was : 642,000

The percent increase was by : 5%

This means the population in 2010 will be :

105/100 * 642000 = 674,100

i) Increase in population is ; 674,100 - 642,000 = 32100 people

ii) The population in 2010 was : 674,100

iii) Population of 2009 = 642000

Population of 2010 = 674,100

Increase in population = 674,100 - 642000 = 32100

Percent increase = increase/ original population * 100

Percent of increase = 32100/642000 * 100 = 5%

User Ziriax
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories