Question

At what distance above the surface of the Earth is the acceleration due to Earth gravity 0.95 metre per second

square​

Answer 1

To Find :

At what distance above the surface of the Earth is the acceleration due to Earth gravity 0.95 meter per second square​.

Solution :

Let, acceleration due to gravity at height h is
`g_h`.

`(g_h)/(g)=(R^2)/((R+h)^2)\\\\((R+h))/(R)=\sqrt{(9.8)/(0.95)}\\\\((R+h))/(R)=3.2\\\\h = 3.2R - R\\\\h = 2.2R\\\\h = 2.2* 6400 \ km \\\\h = 14080\ km`

Therefore, the height is 14080 km.

Hence, this is the required solution.