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You serve a tennis ball of mass 60g at a speed of 50

m/s, what is the impulse exerted on the ball? ( ball starts from rest )

User Styfle
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1 Answer

6 votes

Answer:


J = 3~Kg.m/s

Step-by-step explanation:

Impulse and Momentum

The impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it.

The equation can be written as follows:


J =\Delta p = p_2-p_1

Where:

J = Impulse

p2 = Final Momentum

p2 = Initial Momentum

The momentum can be calculated as:

p = m.v

Where m is the mass of the object and v is the velocity.

The tennis ball with mass m=60 g = 0.06 Kg was served from rest (v1=0) to v2=50 m/s. The change in momentum is:


\Delta p = 0.06Kg~50~m/s-0


\Delta p = 3~Kg.m/s

Thus the impulse is:


\marhbf{J = 3~Kg.m/s}

User David Kay
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