Question

Empirical formula for

Ca 40.078 22.3%
As 74.9216 41.6%
O 15.9994 35.6%
H 1.00794 0.560%

Answer 1

The empirical formula : CaAsO₄H

Further explanation

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

• Determine the mass ratio of the constituent elements of the compound.
• Determine the mole ratio by by dividing the percentage by the atomic mass

• Ca

`\tt (22.3)/(40.078)=0.556`

• As

`\tt (41.6)/(74.9246)=0.555`

• O

`\tt (35.6)/(15.9994)=2.225`

• H

`\tt (0.56)/(1.00794)=0.556`

Divide by the smallest ratio(0.555) :

Ca : As : O : H ⇒

`\tt (0.556)/(0.555)/ (0.555)/(0.555)/ (2.225)/(0.555)/ (0.556)/(0.555)=1/ 1/ 4/ 1`