1 Answer

Suresh Cheemalamudi · Answer 1 · 2021-10-02T03:13:04+0000

Answer:

The inner surface area of a hemispherical bowl will be: 1923.25 cm²

Explanation:

Given

d = 35 cm

as

r=(d)/(2)

=(35)/(2)

= 17.5 cm

The inner surface area of a hemispherical bowl = 2πr²

$=2* 3.14* \left(17.5\right)^2$

$=6.28\:* \:17.5^2$

=1923.25

Hence, the inner surface area of a hemispherical bowl will be: 1923.25 cm²

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