Answer:
The directional earing is N 30° E
Explanation:
The given velocity vector is (25, 25·√3), therefor, we have;
R = 25·i + 25·√3·j
The angle of inclination of the direction of the boat with the horizontal = Arctan (y/x)
Where;
(x, y) = The coordinate of the components of the velocity of the boat
Therefore;
Arctan (y/x) = Arctan (25·√3/25) = Arctan (√3) = 60° North of East
The directional bearing which is the bearing relative to the northern direction is given as follows;
The directional earing = 90° - 60° = N 30° E.