Answer:
![m=-(3)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/on0atu9k0da9n267p7orca1r5jn9quoono.png)
Explanation:
First, look at the graph and pick out two points that we can use for the slope equation. I see (0,2) and (-2,5) as two possibilities. Now, we just plug them into the slope equation. Remember that the slope equation is
![m=(y2-y1)/(x2-x1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/s22vchztbo0z3zfbr5dy5rbx0ndd5ffwx5.png)
(the '2' and '1' are subscripts, not exponents)
Let's call our first point (0,2) x1 and y1. (-2,5) can be the second point.
If we plug this into the equation:
![m=(5-2)/(-2-0)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zzbvq1krwygjxu7o59rzuxc1upi8nhq4nz.png)
Now we just simplify and get
![m=(3)/(-2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1gyj2r3epup3vt7flxbhubp15f1t460192.png)
Our slope is
.
I hope this helps!