Question

Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)​

Answer 1

pH of solution = 9.661

Further explanation

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

pOH=-log[OH⁻]

`\tt pOH=-log[4.583* 10^(-5)]\\\\pOH=5-log~4.583=4.339`

pH+pOH=pKw

`\tt pH=14-4.339\\\\pH=9.661`