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How many atoms are in 1.4 mol of phosphorus trifluoride (PF3)?

1 Answer

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Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³

Further explanation

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :


\tt N=1.4* 6.02* 10^(23)\\\\N=8.428* 10^(23)

User A Mehmeto
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