Question

Help! this is algebra 1 and idk how to do it lol

Answer 1

a. x+6 = 0

b. y-2 = 0

Explanation:

Given point is:

(-6,2)

a. Line perpendicular to x-axis:

A line perpendicular to x-axis means that the line is vertical and parallel to y-axis. Any equation parallel to y-axis has the form

x = k

where k is the x-coordinate of the point from which the line passes.

So the required equation is:

`x = -6\\x+6 = 0`

b. Line perpendicular to y-axis:

A line perpendicular to y-axis will be a horizontal line parallel to x-axis having the equation of the form

y = b

where b is the y-intercept

Required equation is:

`y = 2\\y-2=0`

Hence,

a. x+6 = 0

b. y-2 = 0