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Given:a || b m<2=3x+20 m<7=2x-10 find:m<3, m<6

Given:a || b m<2=3x+20 m<7=2x-10 find:m<3, m<6-example-1
User Jnmoal
by
5.7k points

2 Answers

3 votes

Answer: 48=19 X 2

Explanation:

its allin the math

User Pingu
by
6.0k points
2 votes

Answer:

3(34) + 20 -> Angle 6 = 122

2(34) - 10 -> Angle 3 = 58

Explanation:

Since measure of angle 2 is equal to measure of angle 6, and measure of angle 7 is equal to measure of angle 3, we can determine the angle measures for angle 3 and angle 6.

First, we solve for x by adding together the two equations and setting it equal to 180 because of the supplementary angles theorem.

3x + 20 + 2x - 10 = 180

Combine like terms.

5x + 10 = 180

Subtract 10, then divide by 5 on both sides.

5x = 170

x = 34

Now we can plug the x value into the equations.

3(34) + 20 -> Angle 6 = 122

2(34) - 10 -> Angle 3 = 58

#teamtrees #WAP (Water And Plant)

User Etarion
by
5.4k points
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