Question

A grocery store is offering a sale on bread and soup. Khalil buys four cans of soup and

three loaves of bread for $11.67. Ronda buys eight cans of soup and one loaf of bread for $12.89.
Homework. Help
a. Write equations for both Khalil's and Ronda's purchases.
b. Solve the system to find the price of one can of soup and the price of one loaf of bread

Answer 1

Khalil's equation: 4s + 3b = 11.67
Ronda's equation: 8s + 1b = 12.89
Using the elimination method, we find that the price of one can of soup is $1.35 and the price of one loaf of bread is $2.09.

Step-by-step explanation:

a. Let's say the price of one can of soup is 's' dollars and the price of one loaf of bread is 'b' dollars.

For Khalil's purchase, he buys 4 cans of soup and 3 loaves of bread, which costs $11.67. So we can write the equation: 4s + 3b = 11.67.

For Ronda's purchase, she buys 8 cans of soup and 1 loaf of bread, which costs $12.89. So we can write the equation: 8s + 1b = 12.89.

b. To solve the system of equations, we can use the substitution method or the elimination method. Let's use the elimination method:

Multiplying the first equation by 8 and the second equation by 4, we get:

32s + 24b = 93.36

32s + 4b = 51.56

Subtracting the second equation from the first equation, we get:

20b = 41.8

b = 2.09

Substituting the value of 'b' back into one of the original equations, we can solve for 's':

4s + 3(2.09) = 11.67

4s + 6.27 = 11.67

4s = 5.4

s = 1.35

Therefore, the price of one can of soup is $1.35 and the price of one loaf of bread is $2.09.

Answer 2

a) cblo

2)$3.44

Step-by-step explanation:

4 cans and 3 loaves=11.67

8 cans and 1 loaf= 12.89.

Set up equation:

x=cans

y=loaves

`4x+3y=11.67\\8x+y=12.89` This is the answer for question A.

Multiply eq1 by 2:

`8x+6y=23.34`

Subtract eq3 by eq2:

`5y=10.45\\y=2.09`

Substitute:

`8x+2.09=12.89\\8x=10.8\\x=1.35`

One can of soup and one loaf of bread=

`1.35+2.09 or 3.44`

So:

`$3.44`

Hope this helps :D Please hit the crown if u can !!