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What volume of 3.25m naoh would be required to form 1 mole of na3po4
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What volume of 3.25m naoh would be required to form 1 mole of na3po4

User Manofsins
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1 Answer

6 votes

Answer: 0.923 L

Explanation: The reaction between naoh and h3po4 is:

3naoh + h3po4 —> na3po4 + 3h20

this means it requires 3 mols of naoh to make na3po4

given the concentration, 3.25 M, the equation looks like this:

3.0 mol x (1.0L/ 3.25mol) = 0.923 L

User TheBeardyMan
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