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Hi, anyone able to help with qn 7? Thanks :)!

Hi, anyone able to help with qn 7? Thanks :)!
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1 vote
Hi, anyone able to help with qn 7? Thanks :)!

Hi, anyone able to help with qn 7? Thanks :)!-example-1
User Shawn Lauzon
by
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1 Answer

0 votes

Answer:

Explanation:

I used the quadratic formula to find the roots of
x^(2) + x -1


a=(-1-√(5))/(2) b=(-1+√(5) )/(2)


(1 )/(√(3) ) *((-1-√(5))/(2) )^(2) * (-1+√(5))/(2)


(1 )/(√(3) ) *((-1-√(5))/(2) ) * (-1+√(5))/(2)*((-1-√(5))/(2) )


(1 )/(√(3) ) *((-1-√(5))/(2) ) * (-1+√(5)-√(5) -4)/(4)


(1 )/(√(3) ) *((-1-√(5))/(2) ) * ( -4)/(4)


(1 )/(√(3) ) *((-1-√(5))/(2) ) * -1


(-1-1√(5) )/(2√(3) )*-1


(-1-1√(5) )/(2√(3) ) = (√(5)+1 )/(2√(3) )

User Chris Rymer
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