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Give the values of the coefficients [a], [b], and [c] regarding the product in the form of ax^2+bx+c. Use "0" if the term isn't present.

Give the values of the coefficients [a], [b], and [c] regarding the product in the-example-1
User Daweo
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1 Answer

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Answer: a = 1, b = 0, c = -49

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Step-by-step explanation:

Expand out the expression using the FOIL rule

(x+7)(x-7)

x^2 - 7x + 7x - 49

1x^2 + 0x - 49

We see that a = 1, b = 0, c = -49

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Another way to expand is to do the following

(x+7)(x-7)

y(x-7) .... let y = x+7

xy - 7y .... distribute

x( y ) - 7( y )

x( x+7 ) - 7( x + 7 ) ... replace y with x+7

x^2 + 7x - 7x - 49 .... distribute

1x^2 + 0x - 49

We get the same result.

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Lastly, a shortcut can be used as yet another method to expand.

The shortcut is the difference of squares rule

(a + b)(a - b) = a^2 - b^2

In this case, a = x and b = 7, so,

(a + b)(a - b) = a^2 - b^2

(x + 7)(x - 7) = x^2 - 7^2

(x + 7)(x - 7) = x^2 - 49

(x + 7)(x - 7) = 1x^2 + 0x - 49

User K Tarun
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