Question

Please help

f(x)=1 - 2x g(x)= -x0 h(x)= x + 1
) Find the value of
(i) gf2),
Answer(a)(i)
[2]​

Answer 1

we get
`\mathbf{gf(2)=-(1)/(3)}`

Explanation:

We are given:

`f(x)=1-2x\\g(x)= (1)/(x)\\h(x)=x^3+1`

We need to find value of
`gf(2)`

`gf(2)=g(f(2))`

First putting f(x) inside of g(x) and then putting x=2

`gf(x)=g(f(x))\\gf(x)=(1)/(1-2x)`

Now putting x=2 to find
`gf(2)`

`gf(x)=(1)/(1-2x)\\gf(2)=(1)/(1-2(2))\\gf(2)=(1)/(1-4)\\gf(2)=(1)/(-3)\\gf(2)=-(1)/(3)`

So, we get
`\mathbf{gf(2)=-(1)/(3)}`