Answer:
∠ RQS = 138°
Explanation:
Since PR and PS are tangents to the circle, then
∠ QRP = ∠ QSP = 90°
The sum of the interior angles of PRQS = 360°
Subtract the sum of the interior angles from 360° for ∠ RQS
∠ RQS = 360° - (90 + 90 + 42)° = 360° - 222° = 138°