Question

A machine that operates a ride at the fair requires 2500 J to lift a 294 N child 5.0 m. What is the efficiency of this machine?

Answer 1

η = 58.8%

Step-by-step explanation:

Work is defined as the force applied by the distance traveled by the body.

`W =F*d`

where:

W = work [J] (units of joules)

F = force = 294 [N]

d = distance = 5 [m]

`W = 294*5\\W = 1470 [J]\\`

Efficiency is defined as the energy required to perform an activity in relation to the energy actually added to perform some activity. This can be better understood by means of the following equation.

`efficiency = W_(done)/W_(required)\\efficiency = 1470/2500\\efficiency = 0.588 = 58.8%`