Question

What is the solution to the system: ax+y=18 and 4ax-y=12? Use elimination. Put the answer as an ordered pair. Show work on the next question. You have 3 unknowns and only 2 equations so you can have the variable "a" in your solution

Answer 1

Ax=6

Y=12

Therefore a=6, x=1, y=12

Answer 2

{(
`(6)/(a)`,12)}

Explanation:

`\left \{ {{ax+y=18} \atop {4ax-y=12}} \right.`

`5ax = 30`

`x = (6)/(a)`

`a((6)/(a)) + y = 18`

6 + y =18→y=12

`4a((6)/(a)) - 12 = 12`

6 - 12 = 12 → 12 = 12 true x=
`(6)/(a)` y=12