Answer:
The slopes of three sides of triangle are as follows:
AB = -3
BC = 2/3
AC = -1/4
Explanation:
The slope is denoted by m and is calculated using the formula
![m = (y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qpav2tpezfjoebw1smt5zxyas28f0tlb4m.png)
The given vertices are:
A(-2,4) B(-1,1) C(2,3)
The sides will be:
AB, BC, AC
Let m1 be the slope of AB
Let m2 be the slope of BC
Let m3 be the slope of AC
Now
![Slope\ of\ AB = m_1 = (1-4)/(-1+2) = (-3)/(1) = -3\\Slope\ of\ BC = m_2 = (3-1)/(2+1) = (2)/(3)\\Slope\ of\ AC = m_2 = (3-4)/(2+2) = (-1)/(4) = -(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/bd7k2s8ofqw6wjr021xs583z31yss48ooq.png)
Hence,
The slopes of three sides of triangle are as follows:
AB = -3
BC = 2/3
AC = -1/4