Question

A rolling ball moves from x1 = 8.0 cm to x2 = -4.1 cm during the time from t1 = 2.9 s to t2 = 6.0 s .

Answer 1

Complete Question

A rolling ball moves from
`x_1 = 8.0 \ cm` to
`x_2 = - 4.1 \ cm` during the time from
`t_1 = 2.9 s` to
`t_2 = 6.0s`

What is its average velocity over this time interval?

Answer:

The velocity is
`v = 3.903 \ m/s`

Step-by-step explanation:

From the question we are told that

The first position of the ball is
`x_1 = 8.0 \ cm`

The second position of the ball is
`x_2 = - 4.1 \ cm`

Generally the average velocity is mathematically represented as

`v = ( x_1 - x_2)/(t_2 - t_1)`

=>
`v = ( 8 - -4.1 )/( 6 - 2.9 )`

=>
`v = 3.903 \ m/s`