Complete question :
Ankit makes 74% of the free throws he takes in his basketball league. If he is fouled on a three-point shot and gets three free throws, what is the approximate probability he will make all three shots?
Answer:
0.405224
Explanation:
Given that:
p(success) = p = 74% = 0.74
If given 3 free throws ; probability of making all 3
Using binomial fórmula :
p = 0.74 ;
1 - p = 0.26
P( x = x) = nCx * p^x * (1 - p)^(n-x)
P(x = 3) = 3C3 * 0.74^3 * 0.26^0
P(x = 3) = 1 * 0.405224 * 1
P(x = 3) = 0.405224