Question

Nov 27, 8:06:26 PM

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to
the nearest tenths place.
14
10
Answer:
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Answer 1

The area of given figure is: 179.3

Explanation:

The figure consists of a rectangle and a semi-circle

The length of rectangle is 14 and width is 10.

The width of rectangle is also the diameter of the semi-circle.

So,

d = 10

`r = (d)/(2) = (10)/(2) = 5`

Area of Semi-Circle:

`C =( \pi r^2)/(2)\\= (3.14 * (5)^2)/(2)\\=(3.14*25)/(2)\\=(78.5)/(2)\\= 39.25`

Area of Rectangle:

`R = Length * Width\\R = 10*14\\R = 140`

The total area will be the sum of area of rectangle and the area of semi-circle

So,

`Total\ Area = C + R\\= 39.25 + 140\\=179.25`

Rounding off to nearest tenth

The total area is: 179.3