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What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s? Round to 3 significant

figures
0 2.790 J
5,580 J
025,100 J
050,200 J

1 Answer

3 votes

Answer:

I think C

Step-by-step explanation:

kinetic energy formula: 1/2mv^2

1/2(620kg)(9m/s)^2

1/2(620kg)(81m/s)

1/2(50220)

KE = 25110 J

User Nirdesh Sharma
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