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The graph of f(x) is shown below.

If f(x) and its inverse function, f¹(x), are both plotted on the same coordinate plane, where is their point of intersection?

A. (0,6)
B. (1,4)
C. (2,2)
D(3,0)

The graph of f(x) is shown below. If f(x) and its inverse function, f¹(x), are both-example-1
User TheGeneral
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1 Answer

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The intersection would be at the point (2, 2).

This is because, graphically, the plots of f(x) and its inverse are reflections of one another across the line y = x, and (2, 2) lies on this line.

Put another way, we have f(2) = 2 = f⁻¹(2), so both f(x) and f⁻¹(x) intersect when x = 2.

Put yet another (longer) way, we can find the equation for f(x): it's a line that passes through (0, 6) and (3, 0), so it has slope -6/3 = -2. Then using the point-slope formula,

y - 6 = -2 (x - 0) ⇒ y = f(x) = -2x + 6

By definition of function inverse, we have

f(f⁻¹(x)) = x

so that with the given definition of f(x), we get

f(f⁻¹(x)) = -2 f⁻¹(x) + 6 = x

-2 f⁻¹(x) = x - 6

f⁻¹(x) = -x/2 + 3

Then we solve for x such that f(x) = f⁻¹(x). We would find x = 2 as before.

User Marlen
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