Question

A hockey player skating at 21 m/s comes to a complete stop in 12.0 m.

a) What is its acceleration during this displacement?

b) How long did it take the hockey player to come to a stop?

Answer 1

a. 18.375m/s²

b. 1.142s

Step-by-step explanation:

A. Using v² = u² + 2as

Where;

V = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

s = distance (m)

In this question, v = 21m/s, u= Om/s, s = 12m

21² = 0² + 2 × a × 12

441 = 0 + 24a

441 = 24a

a = 18.375m/s²

B). Using V = u + at

21 = 0 + 18.375t

21 = 18.375t

t = 21/18.375

t = 1.142s