If y =9x^4 - x^3 / x^2 , then dy/dx is: Someone please help

asked Dec 23, 2021 142k views

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If y =9x^4 - x^3 / x^2 , then dy/dx is:
Someone please help

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6 votes

Answer:

(dy)/(dx) = 18x - 1

Explanation:

$y = (9x^(4) - x^(3))/(x^(2) )\\\\y = (9x^(4))/(x^(2) ) - (x^(3))/(x^(2) ) \\\\y = 9x^(2) - x\\\\(dy)/(dx) = 18x - 1$

Andorbal answered Dec 29, 2021

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