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If y =9x^4 - x^3 / x^2 , then dy/dx is: Someone please help

If y =9x^4 - x^3 / x^2 , then dy/dx is: Someone please help
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1 vote
If y =9x^4 - x^3 / x^2 , then dy/dx is:
Someone please help

User Phoenixo
by
7.0k points

1 Answer

6 votes

Answer:


(dy)/(dx) = 18x - 1

Explanation:


y = (9x^(4) - x^(3))/(x^(2) )\\\\y = (9x^(4))/(x^(2) ) - (x^(3))/(x^(2) ) \\\\y = 9x^(2) - x\\\\(dy)/(dx) = 18x - 1

User Andorbal
by
8.3k points
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