Question

A sinusoidal voltage source has a peak voltage of 12 V and a frequency of 50 Hz. What is the voltage at 10 ms?

Answer 1

0

Step-by-step explanation:

Given that:

The peak of the voltage
`V_(peak)` = 12 V

The frequency f = 50 Hz

At the time t = 10 ms

`V = V_p \ sin \ \omega t`

where;

`\omega = 2 \pi f`

`V = 1 2\ V * sin \ ( 2 \pi * 50 * 10 \ )`

V = 12V sin (180)

V = 12 V × 0

V = 0