Answer:
6 Ω
Step-by-step explanation:
given data :
Voltage ( v ) = 12cos ( 60t + 45° )
L = 0.1 H
calculate the inductor's impedance Z
Z = jXL
= jx = 60
= L = 0.1
hence Z = 60 * 0.1 = 6 Ω
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