Question

Perimeter of ABC is 67.

ADC is equilateral and ABC is isosceles. Angle CAB=60, ACB=60 and ACB=60. Find perimeter of triangle ADC.
(Triangle ADB intersects at an angle of 60 deg in triangle ABC.)​

Answer 1

To calculate the perimeter of triangle ADC, understand that since ABC is isosceles with angles measuring 60 degrees and a total perimeter of 67, it is equilateral. Thus, the sides AB, BC, and AC are equal, and the perimeter of ADC, also equilateral, is 100.5.

Step-by-step explanation:

The question involves finding the perimeter of triangle ADC, given that ADC is equilateral, and ABC is an isosceles triangle with angles CAB, ACB each measuring 60 degrees and a total perimeter of 67. Since triangle ABC is isosceles with two angles measuring 60 degrees each, angle B must also be 60 degrees, making triangle ABC equilateral. Therefore, AB = BC = AC. Given that triangle ADC is also equilateral, each side of triangle ADC will be equal to AC.

Let's denote AB = BC = x. Thus, AC = AB + BC = 2x. The total perimeter of ABC is AB + BC + AC = x + x + 2x = 67, so 4x = 67 and x = 16.75. Since ADC is equilateral, each side is AC, which is 2x, so the perimeter of triangle ADC is 3 * 2x = 6x = 6 * 16.75 = 100.5.

Therefore, the perimeter of triangle ADC is 100.5.

Answer 2

man can u send the pic of the diagram I will solve it