Answer:
(c) neither odd nor Even
Explanation:
f(x) odd ⇒ f(-x) = - f(x)
⇒ g(-x) = f(-x) + 2 = - f(x) + 2
Since - f(x) + 2 ≠ - f(x) - 2 and - f(x) + 2 ≠ f(x) + 2
Then g(-x) ≠ - g(x) and g(-x) ≠ g(x)
Then g is neither odd nor even
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