Question

A circular disk of radius 2.0 m rotates, starting from rest, with a constant angular acceleration of 20.0 rad/s2. What is the tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s?a. 40 m/s2.

b. 79 m/s2.
c. zero m/s2.
d. 120 m/s2.
e. 110 m/s2.

Answer 1

Option (a) is correct.

Step-by-step explanation:

Given that,

The radius of a circular disk, r = 2 m

Angular acceleration,
`\alpha =2\ rad/s^2`

We need to find the tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s.

Let a is the tangential acceleration. The relation between the angular acceleration and tengential acceleration. Let it is a.

`a=\alpha r\\\\a=20* 2\\\\a=40\ m/s^2`

So, the tangential acceleration is
`40\ m/s^2`.