Question

What is the frequency of a photon with an energy of 3.38 x 10-19 J?​

Answer 1

b. 5.10 x 10^14 Hz

Step-by-step explanation:

Answer 2

Hey There!

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Answer:

Hz}[/tex]

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DATA:

E =
`3.38 x 10^(-19)`

h =
`6.625x10^(-34)`

f = ?

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SOLUTION:

Energy of Photon is given by,

E = hf

Rearrange the equation,

f =
`(E)/(h)`

where,

E = energy

h = planck's constant

f = frequency

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Substitute the variable in the equation,

f =
`(3.38x10^(-19))/(6.62x10^(-34))`

Simplify the equation,

f = 5.10 x 10^14 Hz

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Best Regards,

'Borz'