Answer:
mass of 50 L of R = 15p + 35q
Explanation:
1L of P = p g
1L of Q = q g
R = 3P + 7Q
total = 10
P = 3/10 R
Q = 7/10 R
R = 50 L
50 L × 0.3 = 15 L the amount of P in L
15 L of P = 15p g
35 L 0f Q = 35 q g
then
mass of 50 L of R = 15 p + 35 q grams